DC Circuit MCQ Job Interview Exam Higher Study Admission Questions Answers part 2
1.
The smallest resistance obtained by
connecting 50 resistance of ¼ each is 1/200.
2.
The internal resistance of a cell of
e.m.f. 2.0 V is 0.1Ω. It is connected to a resistance of 3.9Ω.
The voltage across the cell is 1.9v
Circuit current I=E/R+r= 2.0/3.9+0.1=0.5A,
Voltage across cell V=E-Ir =2.0-(0.5*0.1)=1.95V
3.
Three
2 Ω resistors are connected to form a triangle. The resistance between any two
corner is (4/3) Ω.
4.
A
cell of negligible internal resistance and e.m.f. 2 volts is connected to
series combination of 2, 3 and 5 Ω. The potential difference across the
terminals of 3 Ω resistors will be 0.6V.
5.
A
200 W and 100 W bulb both meant for operation at 220 V are connected in series.
When connected to a 220 V supply, the power consumed by them is 66W.
PT= P1P2/(P1+P2) = 200*100/200+100 = 66 W
6.
An
electric fan and a heater are marked as 100 W, 220V and 1000 W, 220 V
respectively. The resistance of heater is
less than that of fan.
7.
Three
cells each of e.m.f 1.5 V and internal resistance 1 Ω are connected in
parallel. The e.m.f. of the combination is 1.5
V.
8.
When
the internal resistance of a cell is large compared to the external resistance,
then high current is obtained by grouping the cells in parallel.
9.
The
e.m.f. of a cell depends upon electrolyte
and electrodes of the cell.
10.
Given
three equal resistances, combinations
of these three resistances can be
made four.
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